How to extract last 23 digits from this string

breakfreerut rut

I have a string
6.4985424784218431045194480

How can I replace the 23 digits following .49 with ;

Terry R

@breakfreerut-rut said in How to extract last 23 digits from this string:

How can I replace the 23 digits following .49 with ;

Find What:(\.\d\d)\d{23}
with:${1};
This is a regular expression (in case you didn’t know) and used in the Replace function you need the search mode to be regular expression.

Note I took your “.49” as being representative of the first 2 digits following the DOT character “.”. If however you want a replacement ONLY if “.49” is present then the Find regex would be
(\.49)\d{23}

So is the number possibly going to be longer than 25 digits after the DOT character, or maybe shorter. These would be regarded as edge cases as currently the supplied solutions may not give you exactly what you want.

Terry

breakfreerut rut

GREAT! Thanks. The search expression worked.