I would like to group all similar domains, not by alphabet.

Coises

If I understand the problem correctly, my plugin Columns++ can do this.

After installing the plugin, select the entire file and select Sort… from the Columns++ menu.

Fill in the dialog that opens like this:

Screenshot 2023-10-06 125341.png

then click the OK button; click OK again when asked to convert to a rectangular selection.

The settings you need are:

What to sort: Whole lines
Sort type: Descending and Binary
Sort key: Regular expression
Find what: ^[\d.]+\h+(\S*\.)?([^\.\s]+\.[^\.\s]+)
Specify keys using capture groups checked
Keys: 2,1

Locale sort details need not be changed.

I am assuming the “Line _____:” prefixes in your image are not part of the actual file; if they are, then you’ll need to modify the regular expression to account for them.

Also, I took your intent to be to sort first by the domain name, then by the sub-domains (if any), both descending. If you wanted something else, you can consult the help or ask here.

Edit: The regular expression I gave (^[\d.]+\h+(.*\.)?([^\.\r\n]+\.[^\.\r\n]+)(\h.*)?$) was not well-chosen. (It was meant to skip anything following the first or only server name, but it doesn’t do that.) I replaced it with a better one.

guy038

Hello, @mohammad-al-thobiti, @peterjones, @coises and All,

@peterjones, you could have used the same regex, just without changing the dot by the exclamation mark !

Indeed, in this case, we have the rule Regex ( Regex (text) ) = Identity, meaning that after using the regex twice, you text is identical to the orignal one

In addition, I extended the possible links to 4 sections as, for instance, the link ab.cd.ef.com

Thus, starting with this INPUT text :

127.0.0.1   a.dummy-hyphen.org
127.0.0.2   a.example.com
127.0.0.3   cdef.x.example.com
127.0.0.3   b.dummy-hyphen.org
127.0.0.4   b.example.com
127.0.0.6   cd.xyztuv.example.com
127.0.0.5   dummy-hyphen.org
127.0.0.6   example.com

With the regex S/R :

SEARCH (?x) (?<= \h ) ( [\w-]+ ) (?: \. ( [\w-]+ )) (?: \. ( [\w-]+ ) (?: \. ( [\w-]+ ) )? )?
REPLACE (?4$4.)(?3$3.)(?2$2.)(?1$1)

=> You get the temporary text :

127.0.0.1   org.dummy-hyphen.a
127.0.0.2   com.example.a
127.0.0.3   com.example.x.cdef
127.0.0.3   org.dummy-hyphen.b
127.0.0.4   com.example.b
127.0.0.6   com.example.xyztuv.cd
127.0.0.5   org.dummy-hyphen
127.0.0.6   com.example

Perform a ZERO-LENGTH RECTANGULAR selection on all the lines on column 13
Run the Edit > Line Operations > Sort Lines Lexicographically Acsending option

=> Your text becomes :

127.0.0.6   com.example
127.0.0.2   com.example.a
127.0.0.4   com.example.b
127.0.0.3   com.example.x.cdef
127.0.0.6   com.example.xyztuv.cd
127.0.0.5   org.dummy-hyphen
127.0.0.1   org.dummy-hyphen.a
127.0.0.3   org.dummy-hyphen.b

Apply the same regex S/R than previously :

=> You should get the expected OUTPUT text :

127.0.0.6   example.com
127.0.0.2   a.example.com
127.0.0.4   b.example.com
127.0.0.3   cdef.x.example.com
127.0.0.6   cd.xyztuv.example.com
127.0.0.5   dummy-hyphen.org
127.0.0.1   a.dummy-hyphen.org
127.0.0.3   b.dummy-hyphen.org

Best Regards,

guy038

Mohammad Al Thobiti

@ guy038 @ peterjones, @ coises and All
Thank you all
I Removed all 127.0.0.1 lines to avoid any complexity, I left only Domains.
So I can collect it by gropes. After I use it :
With the regex S/R :

SEARCH

(?x) (?<= \h ) ( [\w-]+ ) (?: \. ( [\w-]+ )) (?: \. ( [\w-]+ ) (?: \. ( [\w-]+ ) )? )?

REPLACE

(?4$4.)(?3$3.)(?2$2.)(?1$1)

I had an error (Find: Invalid Regular Expression) after entering the regular expression.

How can I Fix it? whit only domains using

/.example.com/s

and not for all subdomains, because some of them are too long more than 4 sections, for instance, the link

ab.cd.ef.com

as you said.
Thank you.

Mohammad Al Thobiti

/.example.com/s

\.example.com\s

guy038

Hi, @mohammad-al-thobiti, @peterjones, @coises and All,

Ah… OK ! As you prefered to delete the leading IP adresses and the following blank characters, as well, the regex S/R must be changed as :

SEARCH (?x) ( [\w-]+ ) (?: \. ( [\w-]+ )) (?: \. ( [\w-]+ ) (?: \. ( [\w-]+ ) )? )?
REPLACE (?4$4.)(?3$3.)(?2$2.)(?1$1)

So, from this example of INPUT text :

a.dummy-hyphen.org
a.example.com
cdef.x.example.com
b.dummy-hyphen.org
b.example.com
cd.xyztuv.example.com
dummy-hyphen.org
example.com

…At the very end…, you should get this OUTPUT text :

example.com
a.example.com
b.example.com
cdef.x.example.com
cd.xyztuv.example.com
dummy-hyphen.org
a.dummy-hyphen.org
b.dummy-hyphen.org

BTW, to know the maximum of sections of your URL adresses, contained in your file :

First, copy your URL file list as sections.txt
Open the sections.txt within Notepad++
Use the following regex S/R :
- SEARCH [^.\r\n]
- REPLACe Leave EMPTY
- Tick the Regular expression search mode
- Clik on the Replace All button

=> You should get a list of dots ONLY

Now, run the Edit > Line Operations > Sort Lines Lexicographically Ascending option ( No selection needed )
Go to the very end of the sections.txt file ( Ctrl + End )
Simply, count the number of dots of the last line
Delete this dummy file !

Could you tell us which is this number ? Thanks !

BR

guy038

Mohammad Al Thobiti

@ guy038
Oh, Thank you.
some of them work well, but not all as you can see below:

guy038

Hi, @mohammad-al-thobiti and All,

This is the expected behaviour because these addresses contain 5 sections :

anaisdormoy.com.google.accounts.com
<----1----> <2>.<-3--> <--4---> <5>

And my regex works ONLY IF up to 4 dots only !

So, as I asked you in my previous post, just do the second part steps to determine how many sections contains your file !

See you later !

BR

guy038

Mohammad Al Thobiti

Could you tell us which is this number?

The number is 13 dots!

guy038

Hello @mohammad-al-thobiti and All,

Ah… OK !! So, give me some time to find out the correct regex S/R which could handle and revert up to 13 sections !!

See you later,

Best Regards

guy038

Coises

This post is deleted!

PeterJones

@Coises said in I would like to group all similar domains, not by alphabet.:

Commas are not allowed in domain names, so we can use a comma to distinguish between forward and reversed domain names

… which is why I used the historical standard of exclamation points for reversed domain names, rather than introducing ambiguity by re-using the period.

, and reverse them one part at a time:

I do like the way that simplifies the regex, to make it much more understandable and generic, at the expense of making the user click Replace All up to 13 times.

Ugh. You deleted your post while I was replying. It had good information. I am hoping you are going to re-post a slightly rephrased version eventually.

@guy038 said,

So, give me some time to find out the correct regex S/R which could handle and revert up to 13 sections !!

That’s why I just gave the generic format in my original regex, and explained how @Mohammad-Al-Thobiti could extend the idea to as many groups as was desired, because I had a feeling in my reply that the original three-section solution wasn’t going to be enough. Taking my generic formula and just appending copies of the two tokens that I supplied would have worked up to 9 capture groups – and I was hoping that the other regulars here would have let the OP try to learn from the example, rather than spoonfeeding.

And using the ${ℕ} substitution syntax and (?{ℕ}...) conditional replacement instead of $ℕ and (?ℕ...) in the replacement would have allowed for ten or more groups. Which is what I would have suggested when the OP came back with the inevitable “but what if I want more groups than 9? when I tried to 13 groups, it didn’t work”. Because my expression didn’t use nesting, it wouldn’t require any fancy thought on the part of the user, just literally copy/pasting more of the same sort of token, and the ability to interpret that they needed to count up with each ℕ in the replacement.

But @Coises’ currently-deleted suggestion of just doing a single pair replacement, run many times, would be even simpler to understand than my original suggestion, without the {ℕ} requirements. So I hope @Coises re-posts that solution once he’s comfortable with the wording, because it’s the best solution for easy extending to as many domain pieces as needed.

Coises

@PeterJones said in I would like to group all similar domains, not by alphabet.:

Ugh. You deleted your post while I was replying.

I am sorry about that. It contained a good idea, implemented incorrectly. My “solution” rotated the parts of the domain name rather than reversing them.

I didn’t know about exclamation points being a standard; I’ll use those instead of commas when I figure out how to do this correctly.

I also realized the original poster probably wants domains like xxx.com and xxx.org and xxx.co.uk to sort together, which adds an extra complexity.

PeterJones

@Coises said in I would like to group all similar domains, not by alphabet.:

I also realized the original poster probably wants domains like xxx.com and xxx.org and xxx.co.uk to sort together, which adds an extra complexity.

I think your solution, without that, is sufficient for any reasonable need. If the OP desires that complexity, they can take what we’ve already given them and read the documentation that I linked them to, and figure out the next level themselves. (But if you really want to spend your time on that, I’d recommend doing initial searches from blah.com, blah.co.uk, etc, and turn those into blah,com and blah,co,uk; then use ! as the machine separator. That way it will sort first by the blah, then by any more specific things above, which would keep blah.com and blah.co.uk near each other)

Coises

@Mohammad-Al-Thobiti

Since there are so many levels, and you’re working with a temporary file anyway, we could make this less tricky. At @PeterJones’ suggestion, here we use an exclamation point to distinguish between forward and reversed domain names.

Enter:

Find what : ([^.\s]+)\.([^!\s]+)
Replace with : \2!\1

Replace All repeatedly until it says 0 occurrences were replaced, then sort the file.

If you need to change back to normal domain names after the sort, use:

Find what : ([^!\s]+)!([^.\s]+)
Replace with : \2.\1

and Replace All repeatedly until it says 0 occurrences were replaced.

The steps above will sort first by the top-level domain (.com, .net, etc.). If you need to have, say, whatever.com and whatever.net and whatever.co.uk sort together, then after reversing the domain names, use something like:

Find what : ^([a-z]{2}![a-z]{2}|[^!]+)!(\S+)
Replace with : \2 \1

and Replace All once before sorting. (This is not guaranteed to be correct for every case of two-letter top level domains, but it should get the common ones right.)

To reverse, after sorting, use:

Find what : ^(\S+) (\S+)
Replace with : \2!\1

guy038

Hi, @mohammad-al-thobiti, @peterjones, @coises and All,

Ah, ah ah… I’m very happy to announce that I’ve found out a general regex which can handle any number of sections ;-))

So, let’s begin with this simple INPUT text containing from 2 to 13 sections ( one of each ), pasted in a new tab :

abc.def
abc.def.ghi
abc.def.ghi.jkl
abc.def.ghi.jkl.mno
abc.def.ghi.jkl.mno.pqr
abc.def.ghi.jkl.mno.pqr.stu
abc.def.ghi.jkl.mno.pqr.stu.vwx
abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0
abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0.123
abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0.123.456
abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0.123.456.789
abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0.123.456.789.€±¶
abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0.123.456.789.€±¶.Ø÷ß

Move to the very beginning of the file ( Ctrl + Home )

First, we add the |. string at the beginning of every line, with the following regex S/R :

SEARCH (?x-s) ^ (?= . )
REPLACE |.

Thus, we get :

|.abc.def
|.abc.def.ghi
|.abc.def.ghi.jkl
|.abc.def.ghi.jkl.mno
|.abc.def.ghi.jkl.mno.pqr
|.abc.def.ghi.jkl.mno.pqr.stu
|.abc.def.ghi.jkl.mno.pqr.stu.vwx
|.abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0
|.abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0.123
|.abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0.123.456
|.abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0.123.456.789
|.abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0.123.456.789.€±¶
|.abc.def.ghi.jkl.mno.pqr.stu.vwx.yz0.123.456.789.€±¶.Ø÷ß

Move to the very beginning of the file ( Ctrl + Home )

Now, this is the main regex S/R :

SEARCH (?x-s) ^ ( .* \| ) ( (?: \. (?: (?! \| ) \S )+ )+ ) ( \. (?: (?! \. ) \S )+ )
REPLACE \1\3|\2
Click 14th times on the Replace All button, till you get the message Replace All: 0 occurrences were replaced from caret to end-of-file

=> You should get the temporary text :

|.def|.abc
|.ghi|.def|.abc
|.jkl|.ghi|.def|.abc
|.mno|.jkl|.ghi|.def|.abc
|.pqr|.mno|.jkl|.ghi|.def|.abc
|.stu|.pqr|.mno|.jkl|.ghi|.def|.abc
|.vwx|.stu|.pqr|.mno|.jkl|.ghi|.def|.abc
|.yz0|.vwx|.stu|.pqr|.mno|.jkl|.ghi|.def|.abc
|.123|.yz0|.vwx|.stu|.pqr|.mno|.jkl|.ghi|.def|.abc
|.456|.123|.yz0|.vwx|.stu|.pqr|.mno|.jkl|.ghi|.def|.abc
|.789|.456|.123|.yz0|.vwx|.stu|.pqr|.mno|.jkl|.ghi|.def|.abc
|.€±¶|.789|.456|.123|.yz0|.vwx|.stu|.pqr|.mno|.jkl|.ghi|.def|.abc
|.Ø÷ß|.€±¶|.789|.456|.123|.yz0|.vwx|.stu|.pqr|.mno|.jkl|.ghi|.def|.abc

Move to the very beginning of the file ( Ctrl + Home )

Now, we just to get rid of all the | chars as well as the FIRST dot of each line, with the regex S/R :

SEARCH (?x) ^ \| \. | \|

REPLACE Leave EMPTY

And we get our expected OUTPUT text :

def.abc
ghi.def.abc
jkl.ghi.def.abc
mno.jkl.ghi.def.abc
pqr.mno.jkl.ghi.def.abc
stu.pqr.mno.jkl.ghi.def.abc
vwx.stu.pqr.mno.jkl.ghi.def.abc
yz0.vwx.stu.pqr.mno.jkl.ghi.def.abc
123.yz0.vwx.stu.pqr.mno.jkl.ghi.def.abc
456.123.yz0.vwx.stu.pqr.mno.jkl.ghi.def.abc
789.456.123.yz0.vwx.stu.pqr.mno.jkl.ghi.def.abc
€±¶.789.456.123.yz0.vwx.stu.pqr.mno.jkl.ghi.def.abc
Ø÷ß.€±¶.789.456.123.yz0.vwx.stu.pqr.mno.jkl.ghi.def.abc

So, @mohammad-al-thobiti :

Apply all the above steps against your real file
Run the Edit > Line Operations > Sort Lines Lexicographically Ascending option ( No [rectangular] selection is needed as you just keep the addresses )
Possibly, add back the 127.0.0.1 IPV4 address, followed with two space chars with the regex S/R :
- SEARCH (?x-s) ^ (?= . )
- REPLACE (127.0.0.1 )

Best Regards,

guy038

P.S. :

I’ve just seen the @coises’s solution. I’m going to have a look at its solution which could be more simple than my regex solution !

guy038

Hi, @mohammad-al-thobiti, @peterjones, @coises and All,

@mohammad-al-thobiti, you should use the @coises’s approach, which works much better than mine !!

In addition, in my previous post, I omitted to add the reverse regex to use, once your sort would be done :-((

While the @coise’s method avoids any additional S/R and correctly mentions the reverse regex to run after the sort operation

Note that I slightly Modified the first two @coises’s regexes to get more rigorous ones ( See, at the end of this post the reason for these changes )

Thus, I would propose this road map :

First, from the @coises’s post, I would use this alternate regex formulation :
- SEARCH (?x) ( [^.\r\n]+ ) \. ( [^!\r\n]+ )
- REPLACE \2!\1
- Click 14th times on the Replace All button
Run the Edit > Line Operations > Sort Lines Lexicographically Ascending option ( No [rectangular] selection is needed as you just keep the addresses )
Thirdly, once the sort done, from the @coises’s post, use the alternate reverse regex S/R :
- SEARCH (?x) ( [^!\r\n]+ ) ! ( [^.\r\n]+ )
- REPLACE \2.\1
- Click 14th times on the Replace All button

=> You should get all your addresses back, in the right order

Best Regards,

guy038

P.S. :

@coises uses the \s class of characters, which is equivalent to any of the 25 characters, below, with the regex :

(?x) \t | \n | \x{000B} | \x{000C} | \r | \x{0020} | \x{0085} | \x{00A0} | x{1680} | [\x{2000}-\x{200B}] |\x{2028} | \x{2029} | \x{202F} | \x{3000}

In the highly unlikely event that one of these characters is included in some addresses, I preferred to use the [\r\n] regex, which ONLY avoids these 2 EOL chars in addresses, instead of using the \s regex !

Mohammad Al Thobiti

Thank you for your efforts, my friends.
I would like to tell you that the result is excellent.

But an idea came to me: why not just delete the subdomain and keep only the main domain and then delete the similar ones?
Is there a way to delete long link extensions? And keep the main domain?

Example:

Mohammad Al Thobiti

guy038

Hi, @mohammad-al-thobiti and All,

May I rephrase your question ? Let’s see if we mean the same goal !

So, for example, from the INPUT text, below :

abc.def.ghi.jkl.example.com
all.net
abc.def.example.com
abc.my_site.com
abc.def.ghi.all.net
my_site.com
abc.def.all.net
abc.def.ghi.jkl.mno.opq.my_site.com
example.com

With the following regex S/R :

SEARCH (?x) ^ (?: [\w-]+ \. )* ( [\w-]+ \. [\w-]+ ) $

REPLACE \1

We would get that text :

example.com
all.net
example.com
my_site.com
all.net
my_site.com
all.net
my_site.com
example.com

Then, using the Edit > Line Operations > Remove Duplicates Lines option, we would end up with this OUTPUT :

example.com
all.net
my_site.com

If this is exactly what you expect to, just go ahead !

BR

guy038

Mohammad Al Thobiti

I would like to thank you for your useful information and those who contributed to this topic.

This article has become my reference. It works nicely. Yes, we mean the same goal !

Right now. If you can sort or collect them from the most similar domains, please let me know.

There are too many lines, starting with the most similar domain.

Reason: To find the most “worried” domains because it takes many lines. I will delete them later, as you told us. However, the goal is to discover more domains with many characters or long URLs and I will block them in other programs.

How can this be done?