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    Regular expression - delete last character on line

    Help wanted · · · – – – · · ·
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    • lazarusr
      lazarusr last edited by

      I would be really grateful if someone could help me with a regular expression issue.

      I want to find every line that starts ‘//’ (easy enough) and then delete the last character on that line, which will be a ‘}’.

      I have looked through the documentation and I can’t work out how to do it. What I assume that one has to do is output the whole line bar the last character, but I can’t work out how to do it.

      Any suggestion would be really appreciated.

      Many thanks

      Claudia Frank 1 Reply Last reply Reply Quote 0
      • Claudia Frank
        Claudia Frank @lazarusr last edited by

        @lazarusr

        In regex ^ is the start and $ the end anchor.
        In per line mode (default mode in npp) you would search for

        ^(//.*)\}$
        

        you need to escape the } as this has also a special meaning in regex sytanx
        In replace you would use

        \1
        

        For more information see here.

        Cheers
        Claudia

        lazarusr 1 Reply Last reply Reply Quote 2
        • lazarusr
          lazarusr @Claudia Frank last edited by

          @Claudia-Frank Thanks. Sorted.

          1 Reply Last reply Reply Quote 0
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