How to Replace a Matching Parenthetical up to the First Closing Parenthesis

[Zetawilk]

(Foo,1234567890) (bar)

where the numerical string after Foo, can be any set of numbers, and where this sequence is repeated an indefinite quantity of times in a long list with or without including (bar) on each line.

Task: You must replace (Foo,1234567890) without replacing any instance of (bar).

The regular expressions on http://docs.notepad-plus-plus.org/index.php/Regular_Expressions are not functioning, or else poorly explained in human language.

[Alan Kilborn]

@Zetawilk

Your request is kinda vague, at least to me, but let’s get the ball rolling:

Find: \(\w+,\d+\) <----note the trailing space
Search mode: (obviously) Reg exp

Probably not what you want, but to me it works the way I understand the “spec” that has been presented.

[Zetawilk]

I’m unable to edit the topic post for undisclosed reasons. The set of numbers after (Foo, can be in hexadecimal. I can’t possibly imagine what else you thought was “vague”.

[Alan Kilborn]

Posts are only editable for 3 minutes.

With the new spec, I would try:

Find: (?i)\(\w+,[0-9A-F]+\)

[Zetawilk]

Thank you very much for your assistance. This issue is now resolved.

[guy038]

@zetawilk, @alan-kilborn and All,

@zetawilk, in your initial post, you said :

Task: You must replace (Foo,1234567890) without replacing any instance of (bar)

You’re not asking, here, for any commercial demand. Personally, I would have written, preferably :

Request : replace (Foo,1234567890) without replacing any instance of (bar)

and thanked, in advance, possible repliers, for their [free] help !

Just remember it, in your next posts ;-))

Best regards,

guy038

P.S. :

I just forgot your last post. So, let me temper my criticism because you did thank Alan for his answers !