How to Replace a Matching Parenthetical up to the First Closing Parenthesis

Zetawilk

(Foo,1234567890) (bar)

where the numerical string after Foo, can be any set of numbers, and where this sequence is repeated an indefinite quantity of times in a long list with or without including (bar) on each line.

Task: You must replace (Foo,1234567890) without replacing any instance of (bar).

The regular expressions on http://docs.notepad-plus-plus.org/index.php/Regular_Expressions are not functioning, or else poorly explained in human language.

Alan Kilborn

@Zetawilk

Your request is kinda vague, at least to me, but let’s get the ball rolling:

Find: \(\w+,\d+\) <----note the trailing space
Search mode: (obviously) Reg exp

Probably not what you want, but to me it works the way I understand the “spec” that has been presented.

Zetawilk

I’m unable to edit the topic post for undisclosed reasons. The set of numbers after (Foo, can be in hexadecimal. I can’t possibly imagine what else you thought was “vague”.

Alan Kilborn

Posts are only editable for 3 minutes.

With the new spec, I would try:

Find: (?i)\(\w+,[0-9A-F]+\)

Zetawilk

Thank you very much for your assistance. This issue is now resolved.

guy038

@zetawilk, @alan-kilborn and All,

@zetawilk, in your initial post, you said :

Task: You must replace (Foo,1234567890) without replacing any instance of (bar)

You’re not asking, here, for any commercial demand. Personally, I would have written, preferably :

Request : replace (Foo,1234567890) without replacing any instance of (bar)

and thanked, in advance, possible repliers, for their [free] help !

Just remember it, in your next posts ;-))

Best regards,

guy038

P.S. :

I just forgot your last post. So, let me temper my criticism because you did thank Alan for his answers !