How to delete text after the 2nd specific character in each row

[guy038]

Hi, @crimson-virtuoso, @alan-kilborn, @ekopalypse and All,

Alan, very informative post, indeed ! So, If I correctly understand what you said, this means that :

• If the test, on present line 1816 of the FindReplaceDlg.cpp file, for a possible change of selection range, would have been absent, the \K regex feature would work, while doing a single replace operation, with the Replace button ?

I backup your post’s link for future reference, if any question regarding the weird behavior of the \K feature ;-))

Best Regards,

guy0038

[Alan Kilborn]

@guy038

Well, it wouldn’t be as simple as removing the indicated line, as that would break other functionality.
Truly, though, I haven’t thought too much about it.
While I can kinda read C++, and I can use the Visual Studio debugger to step through its code, it isn’t my strong suit.
Hmm, maybe I don’t have a “strong suit”. (Is that a known expression?)
I leave it to others, but I’m fairly confident in my analysis presented earlier about this; I spent a bit of time single-stepping through it and looking at it.

[Thomas 2020]

@Ekopalypse said in How to delete text after the 2nd specific character in each row:

You can use find to jump through the matches but you cannot use
replace while doing this.

I can’t think of any better.
It would be better to replace “^” with “\A”.

^((\w+ \| ){2})(.+)
\1

[Ekopalypse]

@Pan-Jan said in How to delete text after the 2nd specific character in each row:

I can’t think of any better.
It would be better to replace “^” with “\A”.

Why do you think so? What is the advantage of using \A instead of ^ in this case?

[Thomas 2020]

If I wanted to swap lines one by one
the pattern works from the cursor position.

[Ekopalypse]

@Pan-Jan

the pattern works from the cursor position.

that is correct but this means also that it can match the wrong parts.
Assume the following ( | this should be the caret)

string1 | stri|ng2 | string3 | string5744

in that case it would handle string5744 as the match and NOT string3 | string5744

[Thomas 2020]

@Crimson-Virtuoso said in How to delete text after the 2nd specific character in each row:

string1 | string2 | string3 | string5744
string4001 | string2668 | string1234 | string496
string201 | string202 | string203 | string489

in this example there are 3 x |

[Ekopalypse]

@Pan-Jan

I’m sorry, but I think I’m out.
If you think you’re gonna get anywhere with the way you communicate, good luck with that.
I won’t waste any more time trying to figure out what you might mean.

[Thomas 2020]

[Thomas 2020]

^((\w+ \| ){2})(.+)

can be replaced individually