Hello @eugene-fishgalov, @terry-r and All
Thanks for your two examples, but I still couldn’t imagine the general goal :-(. Here is how I proceeded to get a better idea of the problem :
Firstly, I copied all your Wikipedia article in a new tab.
Secondly, I marked all the ranges <ref>•••••••</ref> with the regex <ref>.*?</ref> in red ( Ctrl + M )
I then clicked on the Copy Marked Text button
After pasting, I sorted all these lines ( Edit > Lines Operations > Sort Lines Lexicographically Ascending )
I re-organized some adjacent ranges <ref>•••••••</ref> one per line
Finally I tried to manually sort this list by similarity and I got :
<ref>AS, Rn. 120, S. 57.</ref>
<ref>AS, Rn. 127 S. 60</ref>
<ref>AS, Rn. 127 S. 60</ref>
<ref>AS, Rn. 129 S. 61</ref>
<ref>AS, Rn. 130 S. 62</ref>
<ref>AS, Rn. 131 S. 62</ref>
<ref>AS, Rn. 131 S. 62</ref>
<ref>AS, Rn. 132 S. 62<</ref>
<ref>AS, Rn. 134 S. 63</ref>
<ref>AS, Rn. 142, S. 71.</ref>
<ref>AS, Rn. 151, S. 77.</ref>
<ref>AS, S. 101, Rn. 186.</ref>
<ref>AS, S. 102, Rn. 189.</ref>
<ref>AS, S. 102, Rn. 190.</ref>
<ref>AS, S. 105, Rn. 194.</ref>
<ref>AS, S. 106, Rn. 195-196.</ref>
<ref>AS, S. 82, Rn. 159, Fn. 238.</ref>
<ref>AS, S. 82, Rn. 159.</ref>
<ref>AS, S. 83, Rn. 161.</ref>
<ref>AS, S. 84, Rn. 161.</ref>
<ref>AS, S. 87, Rn. 164; S. 99; Rn. 184.</ref>
<ref>AS, S. 93, Rn. 174.</ref>
<ref>AS, S. 93-94, Rn. 175.</ref>
<ref>AS, S. 97, Rn. 180.</ref>
<ref>AS, S. 98, Rn. 181.</ref>
<ref>AS, S. 98, Rn. 182.</ref>
<ref>BGHZ 40, 272; 50, 227; 56, 228; 72, 246.</ref>
<ref>BGHZ 58, 188</ref>
<ref>Baur/Stürner, Sachenrecht, 18. Aufl. 2009, § 37 Rn. 48; Vieweg/Werner, Sachenrecht; 7. Aufl. 2015, § 15 Rn. 27</ref>
<ref>Büdenbender, Grundsätze des Hypothekenrechts, JuS 1996, 665.</ref>
<ref>MüKoBGB/Lieder, 7. Aufl. 2017, § 1113 Rn. 83; Baur/Stürner, Sachenrecht, 18. Aufl. 2009, § 37 Rn. 48; Rimmelspacher, Kreditsicherungsrecht, 2. Aufl. 1987, § 10 Rn. 711 ff.</ref>
<ref>Rimmelspacher, Kreditsicherungsrecht, 2. Aufl. 1987, Rn. 714; Vieweg/Werner, Sachenrecht, 7. Aufl. 2015, § 15 Rn. 27.</ref>
<ref>Rimmelspacher, Kreditsicherungsrecht, 2. Aufl. 1987, Rn. 714; Vieweg/Werner, Sachenrecht, 7. Aufl. 2015, § 15 Rn. 27.</ref>
<ref>Vieweg/Werner, Sachenrecht, 7. Aufl. 2015, § 15 Rn. 27</ref>
<ref>[[:Файл:RGZ 150, 1.pdf|RGZ 150, 1]]; BGH [https://dejure.org/1982,163 NJW 1983, 1420].</ref>
<ref>[[:Файл:RGZ 161, 52.pdf|RGZ 161, 52]]; [https://dejure.org/1958,549 BGHZ 28, 164]; [https://dejure.org/2015,13297 BGHZ 206, 69].</ref>
<ref>[https://dejure.org/1959,456 BGHZ 29, 157]</ref>
<ref>[https://dejure.org/1963,7 BGHZ 40, 272]</ref>
<ref>[https://dejure.org/1970,170 BGHZ 53, 144]; [https://dejure.org/1971,21 57, 137]</ref>
<ref>[https://dejure.org/1971,21 BGHZ 57, 137]</ref>
<ref>[https://dejure.org/1973,48 BGHZ 61, 289]</ref>
<ref>[https://dejure.org/1976,124 BGHZ 66, 362]; [https://dejure.org/1976,156 66, 372]; [https://dejure.org/1976,288 67, 75]; [https://dejure.org/1983,140 87, 393, 396]; [https://dejure.org/1983,362 88, 232, 235]</ref>
<ref>[https://dejure.org/1978,150 BGHZ 72, 9, 12]</ref>
<ref>[https://dejure.org/1980,384 BGHZ 78, 216]</ref>
<ref>[https://dejure.org/1983,362 BGHZ 88, 232, 236]</ref>
<ref>[https://dejure.org/1984,281 BGHZ 89, 376]; [https://dejure.org/1984,915 BGH NJW 1984, 2205]</ref>
<ref>[https://dejure.org/1994,893 BGHZ 126, 105]</ref>
<ref>[https://dejure.org/2001,9 BGH NJW 2001, 1127]</ref>
<ref>[https://dejure.org/2002,1296 BGH NJW 2002, 3772]; [https://dejure.org/2003,62 BGHZ 155, 380]; MüKoBGB, § 814, Rn. 12.</ref>
<ref>[https://dejure.org/2008,1843 BGH, 13.02.2008 - VIII ZR 208/07, NJW 2008, 1878].</ref>
<ref>[https://dejure.org/2015,20967 BGHZ 205, 377]</ref>
<ref>[https://dejure.org/2015,4962 BGH, 04.03.2015 - XII ZR 46/13, NJW 2015, 1523.]</ref>
<ref>https://lorenz.userweb.mwn.de/urteile/vizr36_00.htm</ref>
<ref>В данном случае речь идёт не (обязательно) о договоре поручения, а о «указании» в описанном выше кондикционно-правовом смысле. Немецкие термины Anweisender, Angewiesener и Zuwendungsempfänger используются только в рамках этого специфического института, тогда как доверитель и поверенный в собственно-юридическом смысле называются Auftraggeber и Auftragnehmer.</ref>
<ref>В дореволюционном переводе: https://viewer.rusneb.ru/ru/rsl01003642821?page=193 — «удовлетворение»</ref>
<ref>В нем. юриспруденции согласно так называемому «горизонту получателя», нем. Empfängerhorizont.</ref>
<ref>За применение кондикции: [https://dejure.org/1973,841 BGH NJW 1973, 612]; за правило о нарушении основания сделок как специальный закон: [https://dejure.org/1992,508 BGH NJW 1992, 2690].</ref>
<ref>Основанные на: Westermann, Sachenrecht, 5. Aufl. § 128 III 1; Baur, Sachenrecht, 4. Aufl, § 55 B II 2 a</ref>
<ref>Со ссылкой на Kregel in RGRK 11. Aufl. Anm. 8; Staudinger/Spreng, 11. Aufl. Rdz. 10; Palandt/Degenhart, 27. Aufl. Anm. 3 a und Erman/Rinke, 2. Aufl. Anm. 3, к § 1204 ГГУ.</ref>
I, then, understood that we should stay concentrated on the <ref>AS, •••••••</ref> ranges, only ! so, after a manual sorting, I got the shorter list, below :
<ref>AS, Rn. 127 S. 60</ref>
<ref>AS, Rn. 127 S. 60</ref>
<ref>AS, Rn. 129 S. 61</ref>
<ref>AS, Rn. 130 S. 62</ref>
<ref>AS, Rn. 131 S. 62</ref>
<ref>AS, Rn. 131 S. 62</ref>
<ref>AS, Rn. 132 S. 62<</ref>
<ref>AS, Rn. 134 S. 63</ref>
<ref>AS, Rn. 120, S. 57.</ref>
<ref>AS, Rn. 142, S. 71.</ref>
<ref>AS, Rn. 151, S. 77.</ref>
<ref>AS, S. 82, Rn. 159.</ref>
<ref>AS, S. 83, Rn. 161.</ref>
<ref>AS, S. 84, Rn. 161.</ref>
<ref>AS, S. 93, Rn. 174.</ref>
<ref>AS, S. 97, Rn. 180.</ref>
<ref>AS, S. 98, Rn. 181.</ref>
<ref>AS, S. 98, Rn. 182.</ref>
<ref>AS, S. 101, Rn. 186.</ref>
<ref>AS, S. 102, Rn. 189.</ref>
<ref>AS, S. 102, Rn. 190.</ref>
<ref>AS, S. 105, Rn. 194.</ref>
<ref>AS, S. 106, Rn. 195-196.</ref>
<ref>AS, S. 93-94, Rn. 175.</ref>
<ref>AS, S. 82, Rn. 159, Fn. 238.</ref>
<ref>AS, S. 87, Rn. 164; S. 99; Rn. 184.</ref>
Note that one line contains a wrong ending tag <</ref>. You can easily modify these lines with the regex S/R :
SEARCH (<+)|>+
REPLACE ?1<:>
Now, I succeeded to find out a correct regex S/R for almost all the above lines. However, could you tell me how to change the two lines , below :
<ref>AS, S. 82, Rn. 159, Fn. 238.</ref>
<ref>AS, S. 87, Rn. 164; S. 99; Rn. 184.</ref>
For all the other cases, my regex S/R do give the expected result ;-))
See you later,
Best regards,
guy038