Hi Holger. I might be able to help . Just go to my contact form below and send me a sample file. Best regards, Eric Force

http://ericsbanners.com/contact.htm

Yes there is.

I’ve just suddenly ended the N++ process and my session (with all changes) was correctly restored later. Anyway, a forced shutdown is not an elegant way to close Windows, it seems the problem lies at some point between the keyboard and the chair in this case.

Hello, @カヒノビチアレクセイ

Not very difficult, indeed !

If you don’t mind about a final sort of your unique CJK characters, here is a way to achieve it, very quickly :-))

First of all, just backup your original list ( A safe behaviour to adopt, in any case ! )

Now, let suppose you have the following list of CJK characters. I just added, after a space, the Unicode code-point of each character

丰 4E30 不 4E0D 丆 4E06 与 4E0E 不 4E0D 丰 4E30 且 4E14 世 4E16 中 4E2D 且 4E14 与 4E0E 丰 4E30 丟 4E1F 中 4E2D 与 4E0E 中 4E2D 丆 4E06 丰 4E30

First, perform a classical sort, with the menu option Edit > Line Operations > Sort lines Lexicographically Ascending. We get, immediately, the sorted text, below :

丆 4E06 丆 4E06 不 4E0D 不 4E0D 与 4E0E 与 4E0E 与 4E0E 且 4E14 且 4E14 世 4E16 丟 4E1F 中 4E2D 中 4E2D 中 4E2D 丰 4E30 丰 4E30 丰 4E30 丰 4E30

Now :

Move back to the very beginning of your file ( Ctrl + Origin )

Open the Replace dialog ( Ctrl + H )

In the Find what: zone, paste or type the regex (?-s)^(.+\R)\1+

Leave the Replace with: zone EMPTY

Select the Regular expression search mode

Click on the Replace All button

=> You should get, only, the two lines, below :

世 4E16 丟 4E1F

Et voilà !! It just remains the two unique characters of the original list :-))

Notes :

The first part (?-s) is a modifier which implies that any dot will match a single standard character and not EOL characters

Then, the ^ symbol is a zero-length assertion, which means beginning of line

Now, the part (.+\R) represents a non-empty range of consecutive standard characters, followed by its EOL character(s). As the current complete line is enclosed in parentheses, it’s stored as group 1

Finally, the part \1+, is a repeated back-reference to group 1, which looks for any non-empty range of consecutive lines, identical to the first one !

As the replacement zone is EMPTY, all these repeated lines ( > 1 ) are simply deleted !

Best Regards,

guy038

Hello, @Covertraptor90,

Very easy, Indeed !

Move to the very beginning of your file ( Ctrl + Origin )

Open the Replace dialog ( Ctrl + H )

Paste or type the following regex search <drivingSkill>\d\.\d+</drivingSkill>, in the Find what: zone

Paste or type the following replacement text <drivingSkill>1</drivingSkill>, in the Replace with: zone

Select the Regular expression search mode

Click on the Replace All button

Et voilà !

Notes :

The syntax \d matches any single digit, from 0 to 9

The escaped dot \. stands for the decimal dot character. It must be escaped because dot is, normally, a special regex character !

The syntax \d+, identical to \d{1,}, matches any non empty range of consecutive digits

Everything else is just text, which matches itself, in, both, search and replacement !

Best Regards,

guy038

Solved

once i figured out that ^ and $ marks start/end it was easy :)

New to this, dont judge me haha

@Alan-Kilborn

Hi Alan, I assume that 50 is just an arbitrary number, wasn’t able to find any msdn
document which states that this is a limit.

Can’t say anything about python script future plans, unfortunately.

Cheers
Claudia

@moon6969

Hi, nice one but I guess there is little issue as you use

[^\[\]]

whereas, I believe, it should be

[^\[]

because otherwise a text like

blabla] blabla [needed_text] blabala

will break your logic.

Cheers
Claudia

I do agree this is usually the desired behavior. I often copy/paste from various sources and would hate to have all the line endings mixed up.

That said, there is a way to turn it off. You’d need to install a plugin such as LuaScript or PythonScript so that you can call SCI_SETPASTECONVERTENDINGS and set it tofalse.