@guy038 said in Find and increment by 1:

But I just realize that, in case the 45371001190000 number is not on consecutive lines

I’m glad you realized that…

:-)

Here’s the cross-link: https://github.com/notepad-plus-plus/notepad-plus-plus/issues/6281

@Ekopalypse Thanks for looking this up. It makes more sense now. I now assigned some keyboard shortcuts to the binary copy and paste commands.

Hi, @jeroen-borgman, and All,

Thanks for your comment !

The Free Spacing regex mode also allows you to place the different parts of your regex in consecutive lines, with possible comments after a # character, as below :

(?x) # FREE SPACING regex mode (?-is) # DOT regex char = 1 STANDARD char and search SENSITIVE to case ^ # START of CURRENT line boundary ( Added to be more RIGOROUS ! ) \Q # Part BETWEEN uploads\ and /media ( Group 1 ) /media # LITTERAL string /media (/.+?) # Image NAME ( Group 2 ) \) # LITTERAL string ) The ESCAPED form is necessary as PARENTHESES are REGEX chars ! .+ # REMAINING chars of CURRENT line scanned

Just select all these lines and paste them in the Find what: field of the Find dialog ;-))

Note that if your regex must contain a # char, just place use the escaped syntax \# or the character class [#]

Cheers,

guy038

@guy038

Sorry, sorry,… I apologize !
I had stopped to use N++ about a year ago because of other priorities , and I just restart…
Thank you very much ,

Hello, @bob-johnson, @terry-r and All,

OK, Bob. Luckily your S/R does not change the columns order, as you just want to replace 1 char with a single char, too. So, given the sample text below :

Column 4455555555 8901234567 0 ABCDE VWXYZ - 12345 # - at column 48 0 ABCDE VWXYZ - 12345 # - at column 49 0 ABCDE VWXYZ -BCDEFG 12345 # - at column 50 0 ABCDE VWXYZ A-CDEFG 12345 # - at column 51 0 ABCDE VWXYZ AB-DEFG 12345 # - at column 52 0 ABCDE VWXYZ ABC-EFG 12345 # - at column 53 0 ABCDE VWXYZ ABCD-FG 12345 # - at column 54 0 ABCDE VWXYZ ABCDE-G 12345 # - at column 55 0 ABCDE VWXYZ - 12345 # - at column 56 0 ABCDE VWXYZ - 12345 # - at column 57

The following regex S/R :

SEARCH (?-s)^.{49}.{0,5}\K-

REPLACE .

Tick the Wrap around option

Click on the Replace All button

And choose, of course, the Regular expression search mode

It should modify the text, as expected :

Column 4455555555 8901234567 0 ABCDE VWXYZ - 12345 # - at column 48 0 ABCDE VWXYZ - 12345 # - at column 49 0 ABCDE VWXYZ .BCDEFG 12345 # - at column 50 0 ABCDE VWXYZ A.CDEFG 12345 # - at column 51 0 ABCDE VWXYZ AB.DEFG 12345 # - at column 52 0 ABCDE VWXYZ ABC.EFG 12345 # - at column 53 0 ABCDE VWXYZ ABCD.FG 12345 # - at column 54 0 ABCDE VWXYZ ABCDE.G 12345 # - at column 55 0 ABCDE VWXYZ - 12345 # - at column 56 0 ABCDE VWXYZ - 12345 # - at column 57

Notes :

The first part (?-s) forces the regex engine to consider that dot ( . ) represents a single standard char only ( Not an EOL one )

The special syntax \K, cancels any previous search, already matched, at current location of the regex engine and, in your case, just consider the last - character

Best Regards,

guy038

Thank you very much!

The folder was write protected, after i set the permission to folder and files it still doesnt save the setting.

The config.xml was hidden, so i set it to visible and changed the setting Wrap=“no” to Wrap=“yes”. After restart npp the word wrap was enabled.
But then, if i disabled this setting with the button and restart npp the setting was enabled again (vice versa problem).

Then i started npp one time with right click/admin rights and i noticed a change at the date from the config.xml file. From now on i can change the settings and everything worked now.

Problem solved with your help.
Thanks again :)

@hamadou-mana,

Hello,

I have a big problem and I would like an urgent answer.

I am working on a large .txt file so I would like to replace a suite of vertically aligned data and do not really know how to do it:

the characters present themselves as follows:

1 8 1 1

and I would like to have this:

1 7 1 1

Thank you for helping me

Assuming that’s literally all you have, it would be easy enough

find = 1(\R)8\11\11 replace = 1${1}7${1}1${1}1 search mode = regular expression

The (\R) matches any newline, and saves it into “group 1”. The \1 in the find-expression refers to the value of group1. The ${1} in the replace expression does the same.

If you’ve really got something that is more complicated than that (for example, multiple columns of data, or a non-constant search and/or replace, instead of always 1811 → 1711), you will have to give us a better example of what should and what shouldn’t change, with example data that more fully matches your needs. When giving example data, please highlight it and click the </> button, which will mark it up as “code”, so that the forum doesn’t interpret special characters as Markdown and thus use it for rendering your post; as code, the forum will present the exact data you paste.

Please also study the official Notepad++ regex docs, as well as other resources listed in this forum FAQ

Try with working HTML file for preview

That’s exactly what we’re doing: changing Windows (CR LF) to Unix (LF) with visible line-endings turned on. One can see that the CRs go away and only the LFs are left.

We always double-check it afterward by opening the file in regular Notepad because it’s written in our Standard Operating Procedure – someone, some time in the past, had a problem, but they did not document the problem. They only documented that you needed to check to be sure the conversion “took.” (Very helpful, thank you, person in the past).

Thank you for looking at our problem. It’s baffling.

Thank you very much ! I am going to test it …

@guy038 Thanks for this, works like a charm!
I will study the search syntax with the REGEX doc on the side to do this myself next time.

@computeteen5

You could use the XML Tools plugin and some XSLT code to transform your document.

The following XSLT code creates a copy of the input XML file but doubles the value of the BasePay nodes’ text:

<?xml version="1.0"?> <xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" omit-xml-declaration="no"/> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="BasePay"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:value-of select="text() * 2"/> </xsl:copy> </xsl:template> </xsl:transform>

Save this code as an *.xsl file and open your XML file with Notepad++. I assume that you have already installed the XML Tools plugin.

While your XML file is opened in the active tab, go to (menu) Plugins -> XML Tools -> XSL Transformation. In the dialog popping up click on the ... button, select your XSL file from above and click the Transform button.

@Steven-Haymes said in Updating to 7.8:

how does the “Upgrade Scintilla from 4.1.4 to 4.2.0” effect already installed plugins?

I’m using 7.8 but I’m using portable versions only so can’t say something about installation procedure.
The biggest differences for plugins is that those are able now to load their
dlls from within the plugin directory but it is not forced that the plugin does it.
In short, I did not experience any plugin problems but have to admit, that I do not use so many different plugins.

Success, thanks.

Hex Edit plugin has no longer exist in plugin admin list

@Ekopalypse
That’s…a very good point! It’s more efficient and less cluttered to just have a unique ending delimiter rather than modify the beginning of every line. Thanks!

Hello, @zen2cool and All,

If I understand you, correctly, you would like that, given the text :

+====================== Ticket 16392 ======================= 1 6X50G GO MY LITTLE ONE 2.89 2.89 2.89 B 1 400G NEXP CAT STER STER 3.49 3.49 3.49 B TOTAL EUROS: 3.38

You expect the text :

1 6X50G GO MY LITTLE ONE 2.89 2.89 2.89 B 1 400G NEXP CAT STER STER 3.49 3.49 3.49 B

Am I right about it ? If so, use this regex S/R :

SEARCH (?-is)^.+Ticket.+\R\R|\RTOTAL EUROS.+\R

REPLACE Leave Empty

Best Reards,

guy038