@Mark-Boucher said in Need to replace a line feed character in column 86:
the line feed LF character in column 86 (after MM/YY before *01)
If the pattern is consistent that you have one or two digits, a diagonal, two digits, a line break, and “*01” at the beginning of the next line, then just select Search | Replace… from the menu, enter:
Find what : (?<=\d/\d\d)\R(?=\*01)
Replace with : a single space
Search Mode: Regular expression
and use the Replace All button.
If that gets other sorts of lines that you didn´t want wrapped, then it can be refined, or you can use the counting characters method @Mark-Olson explained.
@Mark-Boucher said in Need to replace a line feed character in column 86:
To accomplish this, I have tried using the Begin/End Select in Column Mode
Rectangular selections won’t work for this, for a couple of reasons. For one thing, you can’t select or change line endings using rectangular selections. In addition, you’re not just selecting the long lines, you’re also selecting “virtual space” past the end of the short lines.