Hello, @app-guide and All,
Easy with regexes !
Open the Replace dialog ( Ctrl + H)
Type in [\d.]+$ in the Find what: zone
Type in \r\n$0 in the Replace with: zone OR \n$0 if you works on an Unix file
Tick the Wrap around option
Select the Regular expression search mode
Click on the Replace All button
Voila :-))
Notes :
The [\d.] regex syntax searches for a single character which can be, either, a digit (\d) or a dot ( . )
Then, the [\d.]+ looks for a non-null range of characters, which can be, either, a digit or a dot
And the [\d.]+$ tries to match the greatest non-null range of digits / dots till the end ( $ ) of current line
In replacement, we first write the line-break characters ( \r\n or \n ), followed with the overall search match ( $0 )
Best regards,
guy038