Hello, @カヒノビチアレクセイ

Not very difficult, indeed !

If you don’t mind about a final sort of your unique CJK characters, here is a way to achieve it, very quickly :-))

First of all, just backup your original list ( A safe behaviour to adopt, in any case ! )

Now, let suppose you have the following list of CJK characters. I just added, after a space, the Unicode code-point of each character

丰 4E30 不 4E0D 丆 4E06 与 4E0E 不 4E0D 丰 4E30 且 4E14 世 4E16 中 4E2D 且 4E14 与 4E0E 丰 4E30 丟 4E1F 中 4E2D 与 4E0E 中 4E2D 丆 4E06 丰 4E30

First, perform a classical sort, with the menu option Edit > Line Operations > Sort lines Lexicographically Ascending. We get, immediately, the sorted text, below :

丆 4E06 丆 4E06 不 4E0D 不 4E0D 与 4E0E 与 4E0E 与 4E0E 且 4E14 且 4E14 世 4E16 丟 4E1F 中 4E2D 中 4E2D 中 4E2D 丰 4E30 丰 4E30 丰 4E30 丰 4E30

Now :

Move back to the very beginning of your file ( Ctrl + Origin )

Open the Replace dialog ( Ctrl + H )

In the Find what: zone, paste or type the regex (?-s)^(.+\R)\1+

Leave the Replace with: zone EMPTY

Select the Regular expression search mode

Click on the Replace All button

=> You should get, only, the two lines, below :

世 4E16 丟 4E1F

Et voilà !! It just remains the two unique characters of the original list :-))

Notes :

The first part (?-s) is a modifier which implies that any dot will match a single standard character and not EOL characters

Then, the ^ symbol is a zero-length assertion, which means beginning of line

Now, the part (.+\R) represents a non-empty range of consecutive standard characters, followed by its EOL character(s). As the current complete line is enclosed in parentheses, it’s stored as group 1

Finally, the part \1+, is a repeated back-reference to group 1, which looks for any non-empty range of consecutive lines, identical to the first one !

As the replacement zone is EMPTY, all these repeated lines ( > 1 ) are simply deleted !

Best Regards,

guy038

Hello, @Covertraptor90,

Very easy, Indeed !

Move to the very beginning of your file ( Ctrl + Origin )

Open the Replace dialog ( Ctrl + H )

Paste or type the following regex search <drivingSkill>\d\.\d+</drivingSkill>, in the Find what: zone

Paste or type the following replacement text <drivingSkill>1</drivingSkill>, in the Replace with: zone

Select the Regular expression search mode

Click on the Replace All button

Et voilà !

Notes :

The syntax \d matches any single digit, from 0 to 9

The escaped dot \. stands for the decimal dot character. It must be escaped because dot is, normally, a special regex character !

The syntax \d+, identical to \d{1,}, matches any non empty range of consecutive digits

Everything else is just text, which matches itself, in, both, search and replacement !

Best Regards,

guy038

Solved

once i figured out that ^ and $ marks start/end it was easy :)

New to this, dont judge me haha

@Alan-Kilborn

Hi Alan, I assume that 50 is just an arbitrary number, wasn’t able to find any msdn
document which states that this is a limit.

Can’t say anything about python script future plans, unfortunately.

Cheers
Claudia

@moon6969

Hi, nice one but I guess there is little issue as you use

[^\[\]]

whereas, I believe, it should be

[^\[]

because otherwise a text like

blabla] blabla [needed_text] blabala

will break your logic.

Cheers
Claudia

I do agree this is usually the desired behavior. I often copy/paste from various sources and would hate to have all the line endings mixed up.

That said, there is a way to turn it off. You’d need to install a plugin such as LuaScript or PythonScript so that you can call SCI_SETPASTECONVERTENDINGS and set it tofalse.

Also, after several minutes, I receive the message:
“Failure retrieving contents of directory /”

@Martin-Bedan

removing the read-only flag doesn’t change the content of a file but
of course makes a process able to do changes again so it might be that
some queued changes do get flushed as soon as the process determines that it can
write to the file. But this is not the behavior of npp.

Cheers
Claudia

@Obada-Kurdi

Okay, so technically it isn’t possible to directly say “Replace lines X through Y” with something else. That being said, there are some ways to achieve the goal.

In your specific case, with X=1 and Y=189, it becomes fairly easy:

Step 1: Move your caret to the very top of your file (important)

Step 2: Execute the following “Replace” operation (not “Replace All”!):

Find-what: (?-s)(.*\R){189} Replace-with: whatever you want Search-mode: Regular expression

However, in the general case (where the starting line X is NOT equal to 1), things are more interesting/tricky. Here’s a solution for that general case, unfortunately it requires you to do some mental math:

Step 1: Move your caret to the very top of your file (important)

Step 2: Execute the following “Replace” operation (not “Replace All”!):

Find-what: (?-s)(.*\R){S}\K(.*\R){L} Replace-with: whatever you want Search-mode: Regular expression

where:

S is the one less than the desired starting line number, note S = X - 1 L is the number of lines it is desired to replace, note L = Y - X + 1

because (from the problem statement):

X is the FIRST line to replace with other data Y is the LAST line to replace with other data

This technically isn’t a Notepad++ question, but more of a Boost regular expression engine question, so I’m reluctant to put forward this solution here, due to less tolerance lately for non-Notepad++ discussion. However, this does have an important N++ implication regarding where the caret is when the replacement is conducted.

If this (or ANY posting on the Notepad++ Community site) is useful, don’t reply with a “thanks”, simply up-vote ( click the ^ in the ^ 0 v area on the right ).

@Мария-Денисова

does this happen when you use no plugins also? You can start npp with -noPlugin switch
or by renaming plugins directory temporarily.

Cheers
Claudia