I had the same problem. I was running v7.3.3 (64 bit). I uninstalled it and installed v7.3.2 (64 bit). It works fine now. :)

@Claudia-Frank or if there is always a space after the number but not in the case with the calling-station you could do find: ^.*(49160\d+)\s.*$ replace: \1

@kawinga , question isn’t formulated clearly but I’m guessing from the screenshot that OP gave that he is referring to indenting paragraphs using tab. I believe your answer of multi-selecting a paragraph and hitting tab pretty much answers the thread. Thanks for that, I didn’t even know you can do that. It’s going to make my life alot easier… :) @Yongtao-Yang , thanks for your answer, that was actually exactly what I was looking for when I wondered into this thread.

@AlexCeed To elaborate a bit on @Claudia-Frank 's explanation, here’s some code that shows how to do a replace on only the text in one or more selections: find = 'a' replace = 'A' num_selections = editor.getSelections() for sel_nbr in range(num_selections): start_pos = editor.getSelectionNStart(sel_nbr) end_pos = editor.getSelectionNEnd(sel_nbr) editor.replace(find, replace, 0, start_pos, end_pos)

@guy038 your SECOND thought should also be to delete this idiot’s account while removing this inane topic. serious users need not waste their time on such junk. thank you, johann

@VampireSeraphin give it a try with the following (regex and match newline needs to be checked) Find what: ^(.*?\r\n)(.*)$ Replace: \1SomeText\r\n\2 ^ Start from beginning of file and the ? restricts to find as less as possible chars until a \r\n (windows end of line marks) appears which basically means the first line. Having enclosed in () means it get captured in variable \1 . Next capture group gets the rest of the text until $ end. In replace you need to add the text and the eols \r\n together with the matching groups. Cheers Claudia