Hello Linda,
regular find/replace wont work because each line is different in those spaces
I don’t understand very well ? May be, your text contains some tabulation character, which don’t match the same physical space length ?
If so, I would advice you, to replace, first, any tabulation by the corresponding amount of space characters, with the menu command Edit - Blank Operations - TAB to Space
Then, taking your previous example, just perform a simple regular search/replace operation like, for instance :
SEARCH = ^.{219}\K... and REPLACE = EMPTY to delete from the 220th till the 222th characters
SEARCH = ^.{219}\K... and REPLACE = ABC to insert a fixed string between the 220th column till the 222th column
SEARCH = ^.{219}\K(...) and REPLACE = [\1] to surround the characters, between the 220th and the 222th, with two square brackets
IMPORTANT :
Due to the special \K syntax, you must use a global replacement, clicking on the Replace All button
If you prefer use a step-by-step replace operation, the different S/R, above, should be rewritten as below :
SEARCH = ^(.{219})... and REPLACE = \1 to delete from the 220th till the 222th characters
SEARCH = ^(.{219})... and REPLACE = \1ABC to insert a fixed string between the 220th column till the 222th column
SEARCH = ^(.{219})(...) and REPLACE = \1[\2] to surround the characters, between the 220th and the 222th, with two square brackets
Hope that helps you a bit !
Best Regards,
guy038
P.S. :
The nice thing, about the \K syntax, is that anything that matched before the \K form, is forgotten by the regex engine! So, in the examples above, the matched string (...) is, ONLY, the three characters, at positions 220, 221 and 222 :-)